Golden-Road.net
Studio 46 - Non-TPiR Discussion => Out In Left Field => Topic started by: 123123123 on December 13, 2012, 10:19:59 PM
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Seeing the other game idea reminded me of mine, so here it is:
The game would be called BlackOut and it would be played for two prizes.
At the onset of the game the contestant would be shown a board with 8 possible prices on the board, with the prices of the prizes being included. Also there would be 6 seperate black boards.
The contestant will have to use the black boards and "blackout" prices that they believe are incorrect. Of course, with six black boards, the odds are not in their favor.
But the cotestant can get rid of up to 4 of the black boards if the can correctly me if the correctly tell me the prices of small prizes (the choices would be either higher, lower or true).
After the side game, the contestant will then "black-out" prices with their remaining boards and they win any of the prizes left uncovered. I hope this trial clears it up:
_______________________________________ ____
Come on up to the stage Eric, where you will be able to win these prizes.
A wall mirror and a trip to Norway
To win those prizes, you are going to play Blackout.
[4590] [7098]
[2895] [5550]
[8649] [3870]
[9099] [6629]
[****] [****]
[****] [****]
[****] [****]
Now in a moment, I am going to ask you to use these black tiles to blackout prices you think don't belong to either the mirror or the clock. But to make it easier, I help you try to get rid of some of these tiles.
Pricing Portion:
Book Stereo Hat Spatula
$15 $89 $110 $50
Guess: True Higher Lower Lower
Actual: True Lower Lower True
$15 $60 $99 $50
[****] [****]
[4590] [7098]
[2895] [5550]
[8649] [3870]
[9099] [6629]
[****] [****]
[****] [****]
[****] [****]
You got rid of two of the six, so now place these four tiles on prices you think are wrong
(places them on $4590, $2895, $5550 and $9099)
[****] [7098]
[****] [****]
[8649] [3870]
[****] [6629]
Now I hope you're winner. Light up the right prices!
[****] [7098]
[****] [****]
[8649] [3870]
[****] [6629]
Well, you win the trip to Norway. Congrats (Notice the colors coordinate)
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So if the correct price is not covered up they win.....correct?
In the example they only got 2 of the 4 sp's...so ou tof the 6 boards they must use 2 were eliminated leaving 4 visible prices....I see..
Very creative!
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That sounds like a very interesting game.
I am curious, though, whether you could give a graphic example with pictures, because I can understand better visually like that. I think I have it understood, but just want to make sure.
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That sounds like a very interesting game.
I am curious, though, whether you could give a graphic example with pictures, because I can understand better visually like that. I think I have it understood, but just want to make sure.
Sure, here is a logical sequence of graphics that correspond to the above trial:
(http://i1150.photobucket.com/albums/o608/123123123183/pieces1_zpsf64e7d9a.jpg)
(http://i1150.photobucket.com/albums/o608/123123123183/blackout11_zps13597d49.jpg)
(http://i1150.photobucket.com/albums/o608/123123123183/blackout111_zps5991335e.jpg)
(http://i1150.photobucket.com/albums/o608/123123123183/blackout21_zpse26b16f2.jpg)
(http://i1150.photobucket.com/albums/o608/123123123183/pieces11_zps8eb77c12.jpg)
(http://i1150.photobucket.com/albums/o608/123123123183/pieces111_zps440228f0.jpg)
(http://i1150.photobucket.com/albums/o608/123123123183/pieces1111_zps02c3ca9f.jpg)
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There are 8 possible prices, and it appears you can eliminate at most 4. You got 2 of the SP/GPs right, so shouldn't that mean you remove two? It appears that you remove four.
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There are 8 possible prices, and it appears you can eliminate at most 4. You got 2 of the SP/GPs right, so shouldn't that mean you remove two? It appears that you remove four.
You don't eliminate any of the prices with the SP's, you lower the number of prices you have to cover up with the black tiles. Since there were 6 black tiles at the start, and 2 of the SP's were guessed correctly, 6-2=4.
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I actually like this; it's very unique. Can't say I can think of another game where the object is to leave yourself with the most amount of prices possible! :lol:
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Let me see if I understand it. The number of SPs guessed right equals the number of black tiles you cover up (you can cover up a maximum of 4 of 6). What do you do with the 8 prices? Place them on the black tiles that you don't cover up? If so, where do you want the prices for the prizes--on the not-covered up tile or not moved at all?
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Let me see if I understand it. The number of SPs guessed right equals the number of black tiles you cover up (you can cover up a maximum of 4 of 6). What do you do with the 8 prices? Place them on the black tiles that you don't cover up? If so, where do you want the prices for the prizes--on the not-covered up tile or not moved at all?
You do not cover the black tiles and the 8 prices don't move, you use the black tiles to cover up prices that are incorrect on the main grid.
At the beginning, you have to cover six of the eight prices with the black boards, since you start with 6 black tiles.
For every correct SP, I lower the number of black tiles. This will, in turn, increase your chances of leaving the correct prices uncovered because you do not have to cover as many
I actually like this; it's very unique. Can't say I can think of another game where the object is to leave yourself with the most amount of prices possible! :lol:
Thanks, I tried to make it as original as possible.
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Okay. So I got the two mixed up. For each of the SPs, you get right, you get to move one fewer blackboards over one of the 8 prices. The idea is to not cover up the two correct prices (or cover up the incorrect prices). If you get 2 SPs correct, you move 4 (6-2=4) blackboards over an incorrect price. If you get 1 SP correct, you move 5 (6-1=5) blackboards. The idea is to move as few blackboards as you can, because the more blackboards you move, the more likely it is that you move a blackboard over the correct price.
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Okay. So I got the two mixed up. For each of the SPs, you get right, you get to move one fewer blackboards over one of the 8 prices. The idea is to not cover up the two correct prices (or cover up the incorrect prices). If you get 2 SPs correct, you move 4 (6-2=4) blackboards over an incorrect price. If you get 1 SP correct, you move 5 (6-1=5) blackboards. The idea is to move as few blackboards as you can, because the more blackboards you move, the more likely it is that you move a blackboard over the correct price.
I think you have the concept of the game down now. So do you think it is a reasonable idea?
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This is a GREAT idea for a pricing game! No joke; I'd LOVE to see this on the show! The concept is unique, the difficulty is close to perfect, and it's a nice spin on the pricing method from 5 Price Tags.
Wonderful job, 123. I can't wait to see this on your inevitable next show! :-D
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This is a very creative idea, however I don't think it would work on the show. The main reason - length. It is really long for a 2-Prizer - about as long if not longer than 5 Price Tags. Maybe it would work better if it was for 2 cars? Then again, they don't want a 2 car game either so, eh.
Also, the difficulty seems a tad high on the SP portion since it can be True, Higher, or Lower.
However, again, it is a very creative idea, haven't seen anything like this that I can recall!
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Maybe it would work better if it was for 2 cars? Then again, they don't want a 2 car game either so, eh.
I thought about making it a two-car game, but I didn't think it was hard enough to win. You'd have a better chance of winning 2 cars in this game than you would have at winning 1 car in Pathfinder or Gas Money. (I don't know the numbers, this is just a assumption)
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I agree that the game is very unique, with the best description being the anti-Barker's Markers. However, there are a couple of suggestions I would like to make.
I see this as a turntable game, with the Blackout boards laid out in front of the prices similar to Bonkers and not side-by-side. It makes that weird area next to it when you take them away.
I'm not sure if I like three options for the SP's, but I would most certainly change the third option to "exact" and not "true", because "true" implies the other choice is "false".
The reveal should be thought about again, because I'm not quite sure how somebody would know that the mirror corresponds to red and the trip corresponds to blue. I would say that the host should ask "light up the price of ....", and have that be able to shine through the board should it have been covered up. In this way, the boards are more like black plastic rather than true blackboard material.
Giving away one of the prizes for being uncovered seems too easy. I would say both are uncovered and you win, or you covered up one or two and you lose.
Vader is right with the timing issue, though. One idea is to have only 2 SP's, with each correct answer reducing the number of boards by two.
In all honesty, I would do away with the SP's all together. 8 prices, 4 boards, go.
At the beginning, you have to cover six of the eight prices with the black boards, since you start with 6 black tiles.
I don't know if you meant it this way, but having contestants cover prices and then "reveal" some based on how well they do on the SP portion is a bad idea since you wouldn't be able to see what's underneath.
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Well, from a purely mathematical "random" selection standpoint...the probability of winning the main game is:
With 6 black tiles: 3.6%
With 5 black tiles: 10.7%
With 4 black tiles: 21.4%
With 3 black tiles: 35.7%
With 2 black tiles: 53.6%
Now, the probability of getting a specific number of picks is more complicated, but basically
P(X=x) = nCx * p^x * q^(n-x)
Where p = Probability of success, q = probability of failure, n = # of tries, and x = number of correct answers.
In this case, p = 1/3, q = 2/3, n = 4, and x changes.
Getting rid of 0 tiles: 19.8%
Getting rid of 1 tile: 39.5%
Getting rid of 2 tiles: 29.6%
Getting rid of 3 tiles: 9.9%
Getting rid of 4 tiles: 1.2%
Therefore, the probability of:
Getting rid of 0 tiles and winning: 0.7%
Getting rid of 1 tile and winning: 4.2%
Getting rid of 2 tiles and winning: 6.3%
Getting rid of 3 tiles and winning: 3.5%
Getting rid of 4 tiles and winning: 0.6%
Therefore, the overall probability of winning is 15.3%
To put that into perspective, the probability of winning Gas Money from random selection is 20% I'm not fully sure how to calculate Pathfinders probability, so I won't do that. However, I do remember looking at probabilities a while back and finding most car games like Let 'em Roll, Any Number, and such hover around 25% and most in general hover between 20-30%. Even the probability of winning a game like Danger Price is 25%
However, most 2 prizers and quickies are between 25 - 50%, which is why 15.3% is very very hard for a 2 prizer. (And yeah, even though it's not a "quickie" I'm considering it to be one since all the other 2 prizers are)
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^So let me make sure I understand what you're saying:
1. My assumption was incorrect, at least when talking about Gas Money
2. The game is harder than a significant number of car games, let alone 2-prizers
If this is all true, then I guess it could be a deceptive 2-car game, if you make the SP's hard enough and/or the possible choices deceiving.
Giving away one of the prizes for being uncovered seems too easy. I would say both are uncovered and you win, or you covered up one or two and you lose.
I still feel the contestant should be rewarded for at least figuring out half the puzzle, so instead of the prize, maybe a small cash bonus.
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^So let me make sure I understand what you're saying:
1. My assumption was incorrect, at least when talking about Gas Money
2. The game is harder than a significant number of car games, let alone 2-prizers
Correct.
If this is all true, then I guess it could be a deceptive 2-car game, if you make the SP's hard enough and/or the possible choices deceiving.
Well, not necessarily really deceiving, just about the same difficulty as 5 Price Tags, maybe a tad easier since TRUE is an option as well as H/L.
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I just want to thank all of you guys for your helpful responses.
EDIT: I almost forgot if someone could come up with a better name, I would love to hear it. I'm just not feeling Blackout
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Cover Up? :oldlol:
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Has there ever been a contest for new pricing games on this site?